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Asked in CBSE AIPMT 2002 · Decay law and half-life
Given: N₀=4×10¹⁰, T_1/2=10 days, t=30 days.
Number of half-lives: n=(30)/(10)=3.
Nuclei still undecayed: N=4×10¹⁰×(1/2)³=0.5×10¹⁰.
The question asks how many have decayed, which is the difference.
N₀-N=4×10¹⁰-0.5×10¹⁰=3.5×10¹⁰.
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