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Asked in NEET 2013 · Decay law and half-life
Each decayed nucleus of X becomes one nucleus of Y, so N₀=N_X+N_Y.
X:Y=1:7 gives N/(N₀)=1/8=(1/2)³.
So n=3 half-lives have elapsed.
t=3×20.
t=60 yr.
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