Practice portal › Nuclei › Radioactivity

The half-life of a radioactive sample undergoing α-decay is 1.4×10¹⁷ s. If the number of nuclei in the sample is 2.0×10²¹, the activity of the sample is nearly

Asked in NEET (Oct.) 2020 · Activity and decay constant

Answer: (1) 10⁴ Bq

Step-by-step solution

Given: T_1/2=1.4×10¹⁷ s and N=2.0×10²¹.

Decay constant: λ=(0.693)/(T_1/2)=(0.693)/(1.4×10¹⁷)=4.95×10⁻¹⁸ s⁻¹.

Activity is the disintegration rate: A=λ N.

A=4.95×10⁻¹⁸×2.0×10²¹=0.99×10⁴.

A≈10⁴ Bq.

Why the other options are wrong

More Radioactivity questionsAll Radioactivity questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer