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Asked in NEET (Oct.) 2020 · Activity and decay constant
Given: T_1/2=1.4×10¹⁷ s and N=2.0×10²¹.
Decay constant: λ=(0.693)/(T_1/2)=(0.693)/(1.4×10¹⁷)=4.95×10⁻¹⁸ s⁻¹.
Activity is the disintegration rate: A=λ N.
A=4.95×10⁻¹⁸×2.0×10²¹=0.99×10⁴.
A≈10⁴ Bq.
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