Practice portal › Mechanical Properties of Fluids › Excess Pressure in Drops and Bubbles
Asked in NEET 2022 · Excess pressure
Given: a soap bubble of radius R blown from a solution of surface tension T.
Idea: a soap bubble has two liquid surfaces, so the pressure jump across its wall is twice that of a single drop.
Pᵢₙ=P₀+(4T)/R
T is fixed by the solution and P₀ by the room, so only R changes.
As the bubble expands R grows and (4T)/R falls.
Hence the pressure inside decreases, approaching P₀ from above.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer