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A galvanometer of resistance 100 Ω gives full scale deflection for a current of 1 mA. It is converted into an ammeter of range 0 - 10 A. The shunt required is:

Asked in NEET 2026 · Conversion to ammeter and voltmeter

Answer: (4) 0.01 Ω

Step-by-step solution

The shunt is in parallel with the galvanometer, so both have the same voltage: I_g G=(I-I_g)S.

S=(I_g G)/(I-I_g)=(0.001×100)/(10-0.001)=(0.1)/(9.999).

S≈0.01 Ω.

Why the other options are wrong

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