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Asked in CBSE PMT 1992 · Force on a wire in a field
Given: L=0.5 m, I=1.2 A, B=2 T, with ⃗B perpendicular to the wire.
Idea: F=BIL sin θ, and a perpendicular field makes sin θ=1.
F=BIL.
F=2×1.2×0.5.
=1.2 N.
The direction is perpendicular to both the wire and the field, given by the left-hand rule for the force on a current.
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