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Asked in CBSE PMT 1996 · Crossed electric and magnetic fields
Given: E=20 V m⁻¹ and B=0.5 T, both perpendicular to the motion and to each other.
Idea: constant velocity means zero net force, so the electric and magnetic forces must cancel — a velocity selector.
qE=qvB.
The charge cancels, so the answer is the same for any particle.
v=E/B.
v=(20)/(0.5).
v=40 m s⁻¹.
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