Practice portal › Moving Charges and Magnetism › Moving Coil Galvanometer and its Conversion
Asked in AIPMT 1998 · Conversion to ammeter and voltmeter
Given: G=9 Ω and S=2 Ω in parallel, total current 1 A.
Idea: in a parallel pair the current divides inversely as the resistances — the easier path takes more.
The share through the shunt is G/(G+S) of the total.
Iₛ=1×9/(9+2)=9/(11).
=0.818 A.
To the figures the options carry, 0.8 A.
The remaining 0.18 A goes through the galvanometer, the higher-resistance branch, as it should.
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