Practice portal › Moving Charges and Magnetism › Field of a Circular Loop
Asked in AIPMT 1999 · Centre and axis of a loop
Given: N=1000, I=0.1 A, r=0.1 m.
Idea: B=(μ₀NI)/(2r) at the centre of a coil.
Numerator: μ₀NI=4π×10⁻⁷×1000×0.1=4π×10⁻⁵.
Denominator: 2r=0.2 m.
B=(4π×10⁻⁵)/(0.2)=2π×10⁻⁴.
B=6.28×10⁻⁴ T.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer