A body of mass 3 kg hits a wall at an angle of 60° with a speed of 10 m s⁻¹ and returns at the same angle, as shown in the figure. The impact time was 0.2 s. The force exerted on the wall is

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(1) 150√3 N. Given: m=3 kg, v=10 m s⁻¹, the 60° measured from the wall as the figure marks it, Δ t=0.2 s. Idea: only the component perpendicular to the wall reverses. Perpendicular component: v sin 60°=10×(√3)/2=5√3 m s⁻¹. Change in momentum: Δ p=2mv sin 60°=2×3×5√3=30√3 kg m s⁻¹. F=(Δ p)/(Δ t)=(30√3)/(0.2). F=150√3 N.

A body of mass 3 kg hits a wall at an angle of 60° with a speed of 10 m s⁻¹ and returns at the same angle, as shown in the figure. The impact time was 0.2 s. The force exerted on the wall is

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