A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by

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(2) 41%. Given: the height is increased by 100%, so the new height is 2h. Idea: from rest, v=√2gh, so momentum P=m√2gh goes as √h. (P₂)/(P₁)=√(2h)/h=√2. √2=1.414. Fractional change =√2-1=0.414. That is an increase of about 41%.

A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by

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Why the other options are wrong