Two bodies of mass 4 kg and 6 kg are tied to the ends of a massless string. The string passes over a pulley which is frictionless (see figure). The acceleration of the system in terms of acceleration due to gravity (g) is:

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(2) g/5. Given: m₁=4 kg and m₂=6 kg over a frictionless pulley. Idea: the string is inextensible, so both bodies have the same magnitude of acceleration, and only the difference in weights drives the system. Net driving force =(m₂-m₁)g=(6-4)g=2g. Total mass moved =m₁+m₂=10 kg. a=((m₂-m₁)g)/(m₁+m₂)=(2g)/(10). a=g/5.

Two bodies of mass 4 kg and 6 kg are tied to the ends of a massless string. The string passes over a pulley which is frictionless (see figure). The acceleration of the system in terms of acceleration due to gravity (g) is:

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