Practice portal › Laws of Motion › Newton's Laws and Free-Body Diagrams

A horizontal force 10 N is applied to a block A as shown in the figure. The masses of blocks A and B are 2 kg and 3 kg respectively. The blocks slide over a frictionless surface. The force exerted by block A on block B is:

Asked in NEET 2024 · Applying the second law and free-body diagrams

Figure: Applying the second law and free-body diagrams
Answer: (3) 6 N

Step-by-step solution

Given: F=10 N on A, m_A=2 kg, m_B=3 kg, frictionless surface.

Idea: take the two blocks together first to get the shared acceleration, then look at B alone.

Whole system: a=F/(m_A+m_B)=(10)/(2+3)=2 m s⁻².

Now B on its own: the only horizontal force on it is the contact push N from A.

N=m_Ba=3×2.

N=6 N.

Why the other options are wrong

More Newton's Laws and Free-Body Diagrams questionsAll Newton's Laws and Free-Body Diagrams questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer