Practice portal › Laws of Motion › Friction: Blocks, Belts and Inclines
Asked in NEET 2026 · Friction on belts and accelerating surfaces
Given: m=15 kg, μₛ=0.12, g=10 m s⁻².
Idea: the only horizontal force on the box is static friction from the trolley floor, so that friction is what has to accelerate it.
For the box to move with the trolley: ma≤μₛ N=μₛ mg.
The mass cancels: a≤μₛ g.
aₘₐₓ=0.12×10=1.2 m s⁻².
The 15 kg is not needed — a heavier box needs more force but also has more friction available.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer