Practice portal › Motion in a Plane › Relative Velocity in Two Dimensions
Asked in NEET 1999 · River and boat problems
Given: swimmer at 0.5 m/s, heading 120° from the downstream direction, and reaching the point directly opposite.
Idea: landing directly opposite means the net velocity is straight across, so the swimmer's upstream component must exactly cancel the stream.
The component of his velocity along the flow is 0.5 cos 120°=-0.25 m/s, that is 0.25 m/s upstream.
For the net drift to vanish, the stream must supply 0.25 m/s downstream.
v_water=0.25 m/s.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer