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The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

Asked in NEET 2012 · Range and angle of projection

Answer: (2) θ=tan⁻¹(4)

Step-by-step solution

Given: horizontal range R equals maximum height H.

Idea: write both in terms of u and θ and set them equal; u and g then cancel.

R=(u² sin 2θ)/g=(2u² sin θ cos θ)/g and H=(u² sin²θ)/(2g).

Setting R=H: (2u² sin θ cos θ)/g=(u² sin²θ)/(2g).

4 cos θ=sin θ, so tan θ=4.

θ=tan⁻¹(4), a steep launch as expected.

Why the other options are wrong

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