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A ball is projected with a velocity 10 m s⁻¹ at an angle of 60° with the vertical direction. Its speed at the highest point of its trajectory will be

Asked in NEET 2022 · Velocity during flight

Answer: (2) 5√3 m s⁻¹

Step-by-step solution

Given: launch speed 10 m s⁻¹ at 60° to the vertical.

Idea: the angle here is measured from the vertical, so the horizontal component is the sine rather than the cosine of it.

Measured from the horizontal the launch angle is 90°-60°=30°.

At the highest point only the horizontal component survives.

v=10 cos 30°=10 sin 60°=10×(√3)/2=5√3 m s⁻¹.

Why the other options are wrong

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