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Asked in NEET 1991 · Distance and average speed
Given: three equal thirds of the distance at 10, 20 and 60 km/h.
Idea: average speed is total distance over total time, and each third takes a different time.
Let the total distance be s, so each leg is s/3.
Total time =s/(30)+s/(60)+s/(180)=(6s+3s+s)/(180)=(10s)/(180)=s/(18).
Average speed =s/(s/18)=18 km/h.
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