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A particle moves along a straight line such that its displacement at any time t is given by s=(t³-6t²+3t+4) metres. The velocity when the acceleration is zero is

Asked in NEET 1994 · Acceleration by differentiation

Answer: (4) -9 m/s

Step-by-step solution

Given: s=t³-6t²+3t+4.

Idea: locate the time at which the acceleration is zero, then read the velocity there.

v=(ds)/(dt)=3t²-12t+3.

a=(dv)/(dt)=6t-12.

Setting a=0: t=2 s.

v(2)=3(4)-12(2)+3=12-24+3=-9 m/s.

Why the other options are wrong

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