Practice portal › Motion in a Straight Line › Two Bodies under Gravity and Successive Drops

A man throws balls with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time? (Given g=9.8 m/s²)

Asked in NEET 2003 · Successive drops

Answer: (1) more than 19.6 m/s

Step-by-step solution

Given: balls thrown every 2 s with speed u, g=9.8 m/s².

Idea: for three balls to be airborne together, the first must still be up when the third is released, which happens 4 s after the first throw.

Time of flight: T=(2u)/g.

Requirement: T>4, that is (2u)/(9.8)>4.

u>19.6 m/s.

Why the other options are wrong

More Two Bodies under Gravity and Successive Drops questionsAll Two Bodies under Gravity and Successive Drops questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer