A ball is thrown vertically upward. It has a speed of 10 m/sec when it has reached one half of its maximum height. How high does the ball rise? (Take g=10 m/s²)

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(1) 10 m. Given: speed 10 m/s at height h/2, g=10 m/s², and the ball comes to rest at the top. Idea: apply v²=u²-2gs between the half-height and the top, where the velocity is zero. That avoids needing the launch speed at all. From the half-height to the top the ball rises a further h/2. 0=(10)²-2(10)(h/2). 100=10h, so h=10 m.

A ball is thrown vertically upward. It has a speed of 10 m/sec when it has reached one half of its maximum height. How high does the ball rise? (Take g=10 m/s²)

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