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Asked in NEET 2016 Phase-I · Integrating a variable acceleration
Given: v=At+Bt², between t=1 s and t=2 s.
Idea: distance is the integral of the velocity, and v stays positive over this interval, so no splitting is needed.
s=∫₁²(At+Bt²)dt=[(At²)/2+(Bt³)/3]₁².
At t=2: (4A)/2+(8B)/3=2A+(8B)/3.
At t=1: A/2+B/3.
Subtracting: s=(3A)/2+(7B)/3.
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