Practice portal › Motion in a Straight Line › Motion with Variable Acceleration

The velocity of a particle moving along a straight line is v=At+Bt², where A and B are constants. The distance travelled by the particle between t=1 s and t=2 s is

Asked in NEET 2016 Phase-I · Integrating a variable acceleration

Answer: (1) (3A)/2+(7B)/3

Step-by-step solution

Given: v=At+Bt², between t=1 s and t=2 s.

Idea: distance is the integral of the velocity, and v stays positive over this interval, so no splitting is needed.

s=∫₁²(At+Bt²)dt=[(At²)/2+(Bt³)/3]₁².

At t=2: (4A)/2+(8B)/3=2A+(8B)/3.

At t=1: A/2+B/3.

Subtracting: s=(3A)/2+(7B)/3.

Why the other options are wrong

More Motion with Variable Acceleration questionsAll Motion with Variable Acceleration questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer