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A body of weight 72 N moves from the surface of earth at a height half of the radius of earth, then gravitational force exerted on it will be

Asked in NEET 2000 · Variation with height

Answer: (2) 32 N

Step-by-step solution

The distance from the centre becomes R+R/2=(3R)/2.

Force falls as the inverse square of that distance.

(F')/F=(R/(3R/2))²=(2/3)²=4/9.

F'=4/9×72.

F'=32 N.

Why the other options are wrong

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