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A particle of mass m is thrown upwards from the surface of the earth, with a velocity u. The mass and the radius of the earth are, respectively, M and R. G is gravitational constant and g is acceleration due to gravity on the surface of the earth. The minimum value of u so that the particle does not return back to earth, is

Asked in NEET 2011 · Escape velocity formula

Answer: (2) √(2GM)/R

Step-by-step solution

The particle just fails to return when it reaches infinity with zero speed.

Energy conservation: 1/2mu²-(GMm)/R=0.

So u²=(2GM)/R.

u=√(2GM)/R, which is the escape speed and equals √2gR since GM=gR².

Why the other options are wrong

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