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The escape velocity from the Earth's surface is v. The escape velocity from the surface of another planet having a radius, four times that of Earth and same mass density is

Asked in NEET 2021 · Comparing planets

Answer: (4) 4v

Step-by-step solution

Escape velocity is vₑ=√(2GM)/R.

At fixed density the mass grows with the volume: M=ρ×4/3π R³.

Substituting, vₑ=√(2Gρ4/3π R³)/R=√(8π Gρ)/3 R.

So at constant density vₑ∝ R.

Four times the radius gives four times the escape velocity: 4v.

Why the other options are wrong

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