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Five capacitors of capacitances C₁=C₂=C₃=C₄=10 μF and C₅=2.5 μF are connected as shown, along with a battery of 50 V. The equivalent capacitance and the charges on each capacitor respectively are:

Asked in NEET 2026 · Capacitor networks

• (1) 5 μF, 125 μC on C₁ to C₄ and 25 μC on C₅
• (2) 4 μF, 250 μC on C₁ to C₄ and 125 μC on C₅
• (3) 5 μF, 250 μC on all capacitors
• (4) 5 μF, 125 μC on all capacitors

Step-by-step solution

Why the other options are wrong

• (1) The equivalent capacitance is right, but C₅ sits directly across the 50 V battery, so it holds 2.5×50=125 μC, not 25 μC.
• (2) No single slip gives 4 μF; the chain C₁ to C₄ is 2.5 μF and it is in parallel with 2.5 μF.
• (3) 250 μC is the total charge drawn from the battery, 5×50; it is shared between two parallel branches, 125 μC each.

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