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There is an electric field E in the x-direction. If the work done on moving a charge of 0.2 C through a distance of 2 m along a line making an angle 60° with the x-axis is 4 J, then what is the value of E?

Asked in CBSE AIPMT 1995 · Work done in moving a charge

• (1) 5 N/C
• (2) 20 N/C
• (3) √3 N/C
• (4) 4 N/C

Step-by-step solution

Why the other options are wrong

• (1) Comes from putting cos 60° in the numerator: E=(W cos 60°)/(qd)=(4×0.5)/(0.4)=5.
• (3) No single slip gives √3; check: 0.2×√3×2×0.5≈0.35 J, far below the 4 J stated.
• (4) No single slip gives 4; check: 0.2×4×2×0.5=0.8 J, not 4 J.

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