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Asked in CBSE AIPMT 2011 Mains · Relation between field and potential
Eₓ=-(∂ V)/(∂ x)=-8x; V does not depend on y or z, so E_y=E_z=0.
At (1,0,2), x=1: Eₓ=-8 V/m.
So the field is 8 V/m along the negative X-axis.
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