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The diagrams below show regions of equipotentials. A positive charge is moved from A to B in each diagram.

Asked in NEET 2017 · Equipotential surfaces and V-r graphs

Figure: Equipotential surfaces and V-r graphs
Answer: (1) In all the four cases the work done is the same.

Step-by-step solution

Work by an external agent moving charge q slowly: W=q(V_B-V_A); it depends only on the end potentials.

In every diagram A lies on the 10 V equipotential and B on the 40 V equipotential.

So V_B-V_A=30 V in all four cases.

The work W=q×30 V is the same in all four.

Why the other options are wrong

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