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Asked in NEET 2017 · Equipotential surfaces and V-r graphs
Work by an external agent moving charge q slowly: W=q(V_B-V_A); it depends only on the end potentials.
In every diagram A lies on the 10 V equipotential and B on the 40 V equipotential.
So V_B-V_A=30 V in all four cases.
The work W=q×30 V is the same in all four.
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