Practice portal › Electromagnetic Induction › Faraday's Law
Asked in NEET 1992 · Induced charge
i=ε/R=1/R(dφ)/(dt), so
q=∫ i dt=1/R∫ dφ=(Δφ)/R.
The time drops out of the integral entirely.
Move the loop quickly and you get a large current for a short time; move it slowly and you get a
small current for a long time, and the charge that flows is the same in both cases, fixed by the
total change in flux.
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