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Asked in NEET 1998 · Mutual inductance and induced EMF
The emf induced in the second coil is ε=-M(dI)/(dt).
(dI)/(dt)=I₀ω cos ω t, whose largest magnitude is I₀ω.
εₘₐₓ=MI₀ω=0.005×10×100π=5π V.
That is about 15.7 V.
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