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Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to the equation I=I₀ sin ω t, where I₀=10 A and ω=100π rad s⁻¹. The maximum value of the emf in the second coil is

Asked in NEET 1998 · Mutual inductance and induced EMF

Answer: (2) 5π

Step-by-step solution

The emf induced in the second coil is ε=-M(dI)/(dt).

(dI)/(dt)=I₀ω cos ω t, whose largest magnitude is I₀ω.

εₘₐₓ=MI₀ω=0.005×10×100π=5π V.

That is about 15.7 V.

Why the other options are wrong

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