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Asked in CBSE AIPMT 2006 · Electric flux through a surface
The area vector of a surface points along its normal. The square lies in the plane of the paper, so its normal points straight out of the page.
The field also lies in the plane of the paper, so it is at right angles to that normal:
φ=E⃗·A⃗=EA cos 90°=0
That the field is confined to the lower half changes nothing. Over the upper half there is no field and hence no flux; over the lower half the field runs parallel to the surface, so no line crosses it there either.
The total flux is zero.
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