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Asked in AIPMT 1991 · Photon energy, momentum and mass
The given wavelength fixes the constant: for the 1 keV photon, (hc)/λ=10³ eV with λ=1.24×10⁻⁹ m.
A 1 MeV photon has 10³ times the energy, so h u=10⁶ eV=10³×(hc)/λ.
Dividing by h: u=(10³c)/λ.
u=(10³×3×10⁸)/(1.24×10⁻⁹)=2.4×10²⁰ Hz.
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