A photocell is illuminated by a source of light, which is placed at a distance d from the cell. If the distance becomes d/2, then the number of electrons emitted per second will be:

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Accepted Answer

(2) four times. For a point source, I∝1/(d²). Halving the distance gives (I₂)/(I₁)=(d/(d/2))²=2²=4. The number of electrons emitted each second follows the intensity, since each electron is freed by one photon. So the count becomes four times as large.

A photocell is illuminated by a source of light, which is placed at a distance d from the cell. If the distance becomes d/2, then the number of electrons emitted per second will be:

Step-by-step solution

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