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In a photoelectric emission process from a metal of work function 1.8 eV, the kinetic energy of the most energetic electrons is 0.5 eV. The corresponding stopping potential is:

Asked in AIPMT 2011 · What the stopping potential depends on

Answer: (3) 0.5 V

Step-by-step solution

The stopping potential is defined by Kₘₐₓ=eVₛ: it is the potential that just turns back the fastest electron.

Here Kₘₐₓ=0.5 eV is given directly.

eVₛ=0.5 eV, so Vₛ=0.5 V.

The work function of 1.8 eV is not needed: it would only be used to work back to the photon energy, which the question does not ask for.

Why the other options are wrong

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