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The de Broglie wavelength of a neutron of mass m in thermal equilibrium with heavy water at a temperature T (in kelvin) is:

Asked in NEET 2017 · Matter waves in other settings

Answer: (1) h/(√3mkT)

Step-by-step solution

A particle in thermal equilibrium at temperature T has average kinetic energy K=3/2kT, being three degrees of freedom at 1/2kT each.

Momentum from kinetic energy: p=√2mK.

Substituting: p=√2m×3/2kT=√3mkT.

de Broglie: λ=h/p=h/(√3mkT).

Why the other options are wrong

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