Practice portal › Current Electricity › Wheatstone Bridge, Metre Bridge and Potentiometer

A uniform metallic wire having resistance 4 Ω is bent to form a square loop (ABCD) (see figure). A resistance of 2 Ω is connected between points B and D and a battery of 2 V is connected across points A and C as shown in the figure. Now the value of current (I) is :

Asked in NEET 2026 · Wheatstone bridge

• (1) 4 A
• (2) 8 A
• (3) 4.5 A
• (4) 2 A

Step-by-step solution

Why the other options are wrong

• (1) Counts each path from A to C as a single 1 Ω side instead of two sides in series; the network would then be 0.5 Ω.
• (2) No single slip gives 8 A; it would need only 0.25 Ω between A and C, less than one side of the square.
• (3) No single slip gives 4.5 A; it would need 4/9 Ω between A and C.

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.