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The resistance of each arm of the Wheatstone's bridge is 10 Ω. A resistance of 10 Ω is connected in series with a galvanometer then the equivalent resistance across the battery will be

Asked in CBSE AIPMT 2001 · Wheatstone bridge

Answer: (1) 10 Ω

Step-by-step solution

Equal arms: (10)/(10)=(10)/(10), the bridge is balanced.

No current in the galvanometer arm, so the 10 Ω in series with it plays no part.

Two branches of 20 Ω in parallel: R_eq=(20×20)/(40)=10 Ω.

Why the other options are wrong

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