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Asked in CBSE AIPMT 2011 Mains · Kirchhoff's laws in networks
Polarity from the figure: in each battery the long plate is +. The 1 V cell has + towards C; the 2 V battery has + towards D.
A to C through the 1 V cell (− to +): V_C=V_A+1=1 V.
Junction C: 1 A arrives from A and 2 A leaves to the right, so 1 A enters C from D through the 2 Ω resistor.
Current flows from D to C, so D is higher: V_D=V_C+1×2=3 V.
D is the + terminal of the 2 V battery and B its − terminal: V_B=V_D-2=1 V.
V_B=+1 V.
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