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A battery of e.m.f 10 V and internal resistance 0.5 Ω is connected across a variable resistance R. The value of R for which the power delivered in it is maximum is given by

Asked in CBSE AIPMT 1992 · Maximum power transfer

Answer: (1) 0.5 Ω

Step-by-step solution

Power in R: P=(E²R)/((R+r)²).

(dP)/(dR)=0 gives R=r.

R=0.5 Ω (maximum power (E²)/(4r)=50 W; the emf does not affect where the maximum lies).

Why the other options are wrong

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