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Two 220 volt, 100 watt bulbs are connected first in series and then in parallel. Each time the combination is connected to a 220 volt a.c. supply line. The power drawn by the combination in each case respectively will be

Asked in CBSE AIPMT 2003 · Rated bulbs and appliances

Answer: (4) 50 watt, 200 watt

Step-by-step solution

Each bulb: R=(220²)/(100)=484 Ω.

Series: 2R, so Pₛ=(220²)/(2R)=(100)/2=50 W.

Parallel: R/2, so Pₚ=(220²)/(R/2)=2×100=200 W.

Answer: 50 watt, 200 watt.

Why the other options are wrong

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