Practice portal › Current Electricity › Electrical Energy and Power
Asked in CBSE AIPMT 2011 · Heating and power in resistors
Power in 9 Ω: (V²)/9=36, so the parallel pair has V=18 V across it.
I₉=(18)/9=2 A and I₆=(18)/6=3 A.
Both currents pass through the 2 Ω resistor: I=2+3=5 A.
V₂=5×2=10 V.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer