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Asked in CBSE AIPMT 2008 · Heating and power in resistors
Heat needed: Q = mcΔ T = 1×4200×80 = 336 000 J.
Power: P = VI = 220×4 = 880 W.
t = Q/P = (336 000)/(880) = 382 s.
t = 6.36 min, i.e. about 6.3 min.
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