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Doubly ionised helium atoms and hydrogen ions are accelerated from rest through the same potential drop. The ratio of the final velocities of the helium and the hydrogen ion is

Asked in CBSE AIPMT 1994 · Links to recoil, photoelectric effect and X-rays

Answer: (3) 1/(√2)

Step-by-step solution

Given: both ions start from rest and fall through the same potential difference V.

Idea: the work done on the charge becomes kinetic energy, 1/2mv²=qV, so v=√(2qV)/m.

A doubly ionised helium atom has q=2e and m=4m_H; a hydrogen ion has q=e and m=m_H.

(v_He)/(v_H)=√(2e/4m_H)/(e/m_H)=√1/2.

So the ratio is 1/(√2): the heavier helium ion ends up the slower of the two.

Why the other options are wrong

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