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The ionisation energy of the electron in the hydrogen atom in its ground state is 13.6 eV. The atoms are excited to higher energy levels to emit radiations of 6 wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between

Asked in CBSE AIPMT 2009 · Number of spectral lines

Answer: (4) n=4 to n=3 states

Step-by-step solution

Idea: the number of distinct lines from level n is (n(n-1))/2.

Setting (n(n-1))/2=6 gives n²-n-12=0, so (n-4)(n+3)=0 and n=4.

The longest wavelength belongs to the smallest energy gap.

Among levels up to n=4 the smallest gap is between n=4 and n=3, worth only 0.66 eV.

So the maximum wavelength comes from the n=4→ n=3 transition.

Why the other options are wrong

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