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The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is

Asked in NEET 2017 · Spectral series and wavelengths

Answer: (3) 4

Step-by-step solution

Idea: the last line of a series is its limit, reached when n₂→∞.

Balmer limit: 1/(λ_B)=R(1/(2²)-0)=R/4, so λ_B=4/R.

Lyman limit: 1/(λ_L)=R(1/(1²)-0)=R, so λ_L=1/R.

(λ_B)/(λ_L)=(4/R)/(1/R)=4.

Why the other options are wrong

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