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The ratio of kinetic energy to the total energy of an electron in a Bohr orbit of the hydrogen atom, is

Asked in NEET 2018 · Energy levels and ionisation

Answer: (2) 1:-1

Step-by-step solution

Idea: for a 1/r attraction, KEₙ=(Rhc)/(n²) while the total energy is Eₙ=-(Rhc)/(n²).

Dividing one by the other, the Rhc/n² cancels completely.

(KEₙ)/(Eₙ)=-1.

So the ratio is 1:-1, whatever the orbit.

Why the other options are wrong

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