Practice portal › Alternating Current › Power in AC Circuits
Asked in NEET 2016 Phase-II · Power factor
The inductor and capacitor voltages oppose each other, so the supply voltage is
V=√V_R²+(V_L-V_C)²=√80²+(100-40)²=√6400+3600=100 V.
The power factor is cos φ=R/Z, and since the same current flows through every
element that ratio equals (V_R)/V.
cos φ=(80)/(100)=0.8.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer