Practice portal › Alternating Current › Resonance in Series LCR
Asked in NEET 2023 · Resonance condition and tuning
f₀=1/(2π√LC), with R playing no part.
LC=(10×10⁻³)(1×10⁻⁶)=10⁻⁸ s², so
√LC=10⁻⁴ s.
f₀=1/(2π×10⁻⁴)=1592 Hz=1.59 kHz.
The units matter here: the answer is a frequency in hertz, and two of the options quote
rad s⁻¹ instead.
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