A 10 μF capacitor is connected to a 210 V, 50 Hz source as shown in the figure. The peak current in the circuit is nearly (π=3.14):

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(2) 0.93 A. The capacitive reactance is X_C=1/(2π fC)=1/(2×3.14×50×10×10⁻⁶)=318.5 Ω. The 210 V is an rms value, so the peak voltage is V₀=√2×210=296.98 V. I₀=(V₀)/(X_C)=(296.98)/(318.5)=0.93 A. Equivalently Iᵣₘₛ=(210)/(318.5)=0.659 A and I₀=√2×0.659=0.93 A.

A 10 μF capacitor is connected to a 210 V, 50 Hz source as shown in the figure. The peak current in the circuit is nearly (π=3.14):

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